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Assignment - AWS

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| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

Assignment

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

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| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

Cover all Basics of Sets

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

Q. Out of 500 car owners investigated, 400 owned Maruti car and 200 owned Hyundai car; 50 owned both cars. Is this data correct?

A B

DC Don’t KnowCan’t Say

NoYes

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

Well Done Ninjas…!!!

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

Well Done Ninjas…!!!

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

Well Done Ninjas…!!!

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

Till Now We Covered...● Bridge Course● Sets● Description of Set● Types of Sets● Cardinal Number of Set● Subset, Universal Set

and Power Set● Venn Diagram● Operations on Sets● Laws of Algebra of Sets● Cardinal Problems

Today’s Objective● Cardinal Problems

(Some Important Results)

● Problems

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

Q. Three sets A, B, C are such that A = B ∩ C and B = C ∩ A, then

A B DC A ⊂ B’A = BA ⊃ B A ⊂ B

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

Q. Let A and B be two sets. The (A ∪ B)’ ∪ (A’ ∩ B) =

A B DC None of theseB’AA’

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

Q. If A = {1, 2, 3, 4, 5}, then number of subsets possible for set A is,

A B DC 3225105

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

Q. If X = {8ⁿ - 7n - 1 | n 𝞊 N} and Y = {49n - 49 | n 𝞊 N}. Then,

A B DC X ⋂ Y = ɸX = YY ⊂ XX ⊂ Y

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

Q. For any three sets A, B and C the set (A ∪ B ∪ C) ∩ (A ∩ B’ ∩ C’)’ ∩ C’ is equal to

A B DC A ∩ B ∩ CB ∩ CB’ ∩ C’B ∩ C’

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

Q. Let A and B be two sets that A ∩ X = B ∩ X = Ø and A ∪ X = B ∪ X for some set X. Then,

A B DC A ∪ B = XB = XA = XA = B

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

WAVE Platform

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

Q. In a college of 300 students, every student reads 5 newspapers and every newspaper is read by 60 students. The number newspaper is

A B

DC None of theseexactly 25

at most 20at least 30

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

Q. If A and B are two sets, then A ⋂ (A ∪ B) equals to

A B DC A ⋂ BɸBA

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

Q. The set (A ⋂ B’)’ ∪ (B ⋂ C) is equal to

A B DC A’ ⋂ BA’ ∪ C’A’ ∪ BA’ ∪ B ∪ C

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

Q. There are 19 hockey players in a club. On a particular day 14 were wearing the prescribed hockey shirts while 11 were wearing the prescribed hockey paints. None of them was without a hockey pant or a hockey shirt. How many of them were in complete hockey uniform?

A B DC 7968

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

Q. Two newspaper A and B are published in a city. It is known that 25% of the city population reads A and 20% reads B while 8% reads both A and B. Further, 30% of those who read A but not B look into advertisements and 40% of those who read B but not A also look into advertisements, while 50% of those who read both A and B look into advertisements. Then, the percentage of the population who look into advertisements is

A B DC 13.912.81313.5JEE mains- 2019

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

Q. In a class of 140 students numbered 1 to 140, all even numbered students opted Mathematics course, those whose number is divisible by 3 opted Physics course and those whose number is divisible by 5 opted Chemistry course. Then, the number of students who did not opt for any of the three courses is

A B DC 13810242

JEE mains- 2019

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

MASTER TEACHER

CLASS TEACHER

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

Let’s Check out the Leaderboard LIVE Classes - Realtime input to Teachers

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

2 years 2 years 2 years

SHJPRO

Start From: 24 May

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

| shimon_joseph Sets | Problem Solving | Lecture 6 | Assignment

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